Set hasDigit to true if the 3-character passCode contains a digit.
#include <iostream>
#include <string>
#include <cctype>
using namespace std;
int main() {
bool hasDigit;
string passCode;
hasDigit = false;
passCode = "abc";
/ Your solution goes here /
if (hasDigit) {
cout << "Has a digit." << endl;
}
else {
cout << "Has no digit." << endl;
}
return 0;
}
Answer:
if (isdigit(passCode.at(0)) || isdigit(passCode.at(1)) || isdigit(passCode.at(2)))
{
hasDigit = true;
}